Forbidden Transitions in Linear Molecules
Strictly the spherical transition
moments T(k,q) should have selection rules ΔS = ΔΣ = 0, but as an
extension PGOPHER relaxes
this requirement and only enforces the
|ΔΩ| = q rule for ΔS ≠ 0 transitions. This will give some intensity
to an otherwise forbidden transition but
does not give enough flexibility in all cases, as several transition
moments may be needed. (For exact simulations give intensity to the
spin
forbidden transition by using perturbations to mix in transitions to
spin allowed states.)
For one photon 1Σ - 3Σ transitions PGOPHER has
enough flexibility as only one parallel (q=0) and one perpendicular (q=1)
component is required. The relative signs of these two are significant
and direct comparison with the results in
the literature requires care; there are two definitions for the
perpendicular component in use:
J.K.G.Watson, Can J Phys 46,
1637 (1968), equation [23]:
μ(1) = 1/√2 < S=0 +- | μ(x) + i μ(y) | S=1, -+, Σ=-1 >
J.T.Hougen, NBS monograph 115, equation [3-27]:
μ(perp) = 1/√2 < S=1, -+, Σ=-1 | μ(x) + i μ(y) | S=0 +- >
The only difference here is the order, but this is essential to the
definition. The two are related as follows:
μ(1) = 1/√2 <
S=0 +- | μ(x) + i μ(y) |
S=1, -+, Σ=-1 >
= 1/√2 { < S=0 +- | μ(x) | S=1, -+, Σ=-1 > + i < S=0 +- | μ(y) | S=1, -+, Σ=-1 > }
= 1/√2 { < S=1, -+, Σ=-1 |
μ(x) | S=0 +- >*+ i < S=1, -+, Σ=-1 | μ(y) | S=0 +- >* }
= 1/√2 < S=1, -+, Σ=-1 |
μ(x) - i μ(y) | S=0 +- >*
= -1/√2 < S=1, -+, Σ=+1 |
μ(x) + i μ(y) | S=0 +- >*
= -μ(perp)*
The complex conjugate can be ignored as μ(1) can be chosen to be real.
(in fact only the ratio μ(1)/μ(0) matters, and as shown by Watson
eq [25], this ratio is real.) PGOPHER
uses the following definition for T(1,1):
T(1,1) = -1/√2 < stateA, Ω+1 |
μ(x) + i μ(y) | stateB, Ω >
with stateA being the state in the bra as shown in the constants
window. If this is 3Σ we have:
T(1,1) = -μ(perp) = μ(1)
but if the bra is 1Σ (reversing the states) the
definition of μ(1) and μ(⊥) does not change but the definition of
T(1,1) does, giving:
T(1,1) = μ(perp) = -μ(1)
The difference is because with PGOPHER
you can select which state is on the
left but e.g. Watson's definition always has the singlet state on the
left, and swapping the states over introduces a minus sign. There is no
such problem with T(1,0) = μ(0) = μ(//).